B
Bart van der Wolf
SNIP
You are correct. Thanks for spotting that.
The "per Picture Height" measurement is a bit tricky with scanners, as
cropping may be different (which it is), although these two seem rather
close.
No, you are right. Assuming the cropping is equal, in the 5400 case there
are 4844 scanned lines per slide's height, whereas in the LS-8000 case there
are 3616. So reaching the same ppi in output requires 34% more magnification
of the LS-8000 scan. That will reduce the LS-8000 from 0.2762 cy/px to
0.2062 cy/px, versus the 0.1963 of the DSE-5400, or 4.8% lower but with
lower contrast and less clipping.
Both scanners seem IMO a bit limited by the film. It would have been nice to
also have a very high drum scan result. That would reveal if there is more
that can be extracted.
Bart
twice.Somehow I have the feeling that you count de difference in resolution
You are correct. Thanks for spotting that.
Your DSE-5400 gets an MTF20 value of 0.1963. This results in
0.1963 * 2 * 4844 = 1902 line/ph.
The LS-8000 gets 0.2762 * 2 * 3616 = 1997.
The "per Picture Height" measurement is a bit tricky with scanners, as
cropping may be different (which it is), although these two seem rather
close.
No matter what you do, you won't get more that 1902 lines (at MTF20) whereas
the LS-8000 gets 1997 lines. Scaling doesn't introduce new lines, and
should not drop lines. Unless, you are saying that higher scaling factors
would somehow result in a serious loss of sharpness.
No, you are right. Assuming the cropping is equal, in the 5400 case there
are 4844 scanned lines per slide's height, whereas in the LS-8000 case there
are 3616. So reaching the same ppi in output requires 34% more magnification
of the LS-8000 scan. That will reduce the LS-8000 from 0.2762 cy/px to
0.2062 cy/px, versus the 0.1963 of the DSE-5400, or 4.8% lower but with
lower contrast and less clipping.
Both scanners seem IMO a bit limited by the film. It would have been nice to
also have a very high drum scan result. That would reveal if there is more
that can be extracted.
Bart