Don, your statement stands and falls by the words you type and your
paragraph above is quoted in full. You make the point that your
absolute statement is "regardless of bit depth" but you have *never*
clarified that you are making a conditional statement in regards to one
particular issue until several posts later.
Because it was implicit (and common sense!) from the start (see below
for explanation) and repeated explicitly several times afterwards when
you brought it up as a side issue.
You keep trying to change the subject and digressing with Analog Gain
and bit depth, etc. all of which have nothing to do with *comparison*
of "raw" vs. "cooked" scans.
What does bit depth have to do with the *comparison* of "raw" vs.
"cooked" scans? You either use 8-bit for *both*, or 16-bit for *both*
but which depth you chose has nothing to do with the comparison of raw
vs. cooked.
Surely, you are not suggesting comparing a "raw 8-bit scan" with a
"cooked 16-bit scan". That would make no sense whatsoever and there is
absolutely no need to exclude such a case explicitly because that's
self-evident and implicit!
I mean, what's next? According to you, should I also have explicitly
stated that the resolution of raw and cooked must be the same? Or that
we should use the same scanner for both? Or that we should do the
scans immediately one after the other? Etc. Etc. Etc.
If you want to parse the original statement to such an absurd degree,
no discussion is possible. There's a common sense context which is
always implied and the same bit-depth, same Analog Gain, same
resolution etc of both scans being compared in the above case are such
a common sense context.
Nothing, however your absolute statement made in response to this that
"*exactly* the opposite is true" has *everything* to do with analogue
gain and any other non-Photoshop edit/control because that is what
exactly opposite means!
But Analog Gain applies (or doesn't) *equally* to both (just like
bit-depth)! So how can Analog Gain make any difference to the
*comparison* if it affects (or doesn't) both sides equally?
You keep ignoring the fact that my objection to your statement was the
precise use of the word "exactly", because it is generally true but not
universally so.
It is universally true within the given (and simple) context of
comparing raw vs. cooked.
A raw scan gives you the purest data, any changes related to color
balance or contrast in scanner software "corrupts" this data.
Therefore, stating that "raw corrupts" is exactly the opposite of the
truth.
If you *unilaterally* start applying Analog Gain to raw, you have
changed the subject because you are no longer comparing raw to cooked,
but "raw + Analog Gain" to "cooked - Analog Gain". And that
"comparison" is senseless. That's both self-evident and implicit.
Don.