Describe a non-analog display system.
Well, again, using the distinction between "analog" and
"digital" which I have been promoting all along, there are
a number of display systems which use what is effectively
a "digital" drive at the pixel level. The Texas Instruments
DMD (Digital Micromirror Device) comes to mind, and
it could be argued that most plasma displays would also
behave in this manner. You seem to favor more of the
common meaning of "digital" (in which "digital" essentially
equates to "binary"), and I would be curious to know how
you would say that such technologies are not "digital" in
that sense as well.
One of the things it means is that the bandwidth of a channel is a
function of its S/N ratio. The greater you can expand that ratio, the
greater the bandwidth.
Well, DUH. At least, "DUH" if you correct one error, and that
is to substitute "information capacity" for the commonly-misused
"bandwidth." ("Bandwidth," in its proper usage, has a very well-
defined meaning which has nothing to do with the noise level; it
is the range of frequencies occupied by the signal information, or
better, the range of frequencies over which a given channel can
deliver a signal without attenuating it to less than half its reference
or "midband" power level.) That's what I've been saying all along - you
DID look up the reference to Shannon, didn't you? To make
things simple, the Shannon formula for the capacity of any
band-limited channel in the presence of noise (read: "any
real-world channel") is
Capacity (bps) = BW * log2 (1 + S/N)
(Note: "log2" should be read as the base 2 logarithm; too
bad I can't do a subscript here.)
That rather clearly states that the capacity is dependent on
both bandwidth and the relative levels of signal and noise,
exactly as one would expect.
For example, a voice-grade telephone line that might only have 4800 Hz
of nominal bandwidth can carry much more than 4800 bps if you can get
the noise level low enough. Modems depend on this, which is how you can
reach 56 kbps on a voice-grade line, if it's quiet enough.
Here again, you confuse "capacity" with "bandwidth." A
voice-grade line ALWAYS has a minimum guaranteed
bandwidth of a given value (it's actually a lot closer to 3000 Hz
than 4800 Hz), AND it has an assumed typical noise level.
It is THOSE values which determine the capacity, per the above
formula. A modem does NOT magically reduce the noise
level on the line; instead, it adapts the information rate in use
to the conditions seen at the time (which is a large part of what
all that "negotiation" is before your dial-up connection is
finally established).
They haven't removed noise, but noise has declined considerably.
Nope. Well, OK, in some markets, it can be argued that
the average level of noise on the line is less today than it was
decades ago, an improvement which has come primarily through
the switch to digital transmission in much of the intermediate
path (with the quantization noise of the digital representation
significantly lower than the other noise sources previously
seen in these sections). But the improvement in modem performance
has not primarily come from improvements on the typical
voice line, but rather through the design of better ("smarter")
modems. There will not be significant advancement beyond the
current 56k level on standard lines, though, since that
performance is now very close to the Shannon limit, given
the standard line specs.
For example, overseas telephone calls today are audibly less noisy than
they were decades ago, even though they have the same specs.
No, they do not have the same specs. The "specs" in question
include minimum expected bandwidth AND the typical/maximum
permissible noise levels. I'm not talking about specs that you as
a customer would normally be seeing.
Bob M.