XSLT Transform Problem

[Guest]

I try to transform xml that has default namespac
For example
<Root xmlns="http://BlaBla.Com"><SomeContent></SomeContent></Root

Then if I use the following xslt I’m getting no results because it expecting the namespace

<xsl:template match="/"><xsl:value-of select="// SomeContent" /></xsl:template

How can I make the xslt transfor
Run under the default namespac
TN

 

[Scott M.]

microsoft.public.xml

I try to transform xml that has default namespace
For example:
<Root xmlns="http://BlaBla.Com"><SomeContent></SomeContent></Root>

Then if I use the following xslt I'm getting no results because it expecting the namespace:

<xsl:template match="/"><xsl:value-of select="// SomeContent"

 

[Derek Slager]

How can I make the xslt transform
Run under the default namespace

You can declare the namespace and qualify it explicitly, as below:

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:blah="http://BlaBla.Com">

<xsl:template match="/">
<xsl:apply-templates select="//blah:SomeContent" />
</xsl:template>

</xsl:stylesheet>

-Derek

 

[Guest]

TNX for your response
but can i use default namespace
something like

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns="http://BlaBla.Com">

<xsl:template match="/">
<xsl:apply-templates select="//SomeContent" />
</xsl:template>

</xsl:stylesheet>

???

 

[Derek Slager]

TNX for your response
but can i use default namespace
something like

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns="http://BlaBla.Com">

<xsl:template match="/">
<xsl:apply-templates select="//SomeContent" />
</xsl:template>

</xsl:stylesheet>

???

I believe that would set the default namespace for your output ... I'm no
XSL expert though, the masters hang out here:

http://www.mulberrytech.com/xsl/xsl-list/

-Derek