W
Wouter
Hi,
I have a Windows 2000 Active Directory domain divided into 5 sites
which are connected with my main site through Win2K PPTP VPN. Each
site has it's own IP range. For example, site 1 has 192.168.1.x, site
2 has 192.168.2.x and so on.
I would like to implement a Win2K DHCP server in each site for my
laptop users, so they don't have to enter their IP addresses manually
when they go to another location of our company. In site 1, the DHCP
server has to provide IP addresses in the 192.168.1.x range, in site 2
it has to provide addresses in the 192.168.2.x range and so on.
Problem is that I don't want the DHCP server in site 1 to provide
addresses to clients in site 2 (through the VPN network, which is in
fact a transparent connection). The DHCP server must only be allowed
to give addresses to clients in it's own site. How do I make sure that
my concern won't happen? And is it possible to have more than one DHCP
server in 1 Active Directory domain, in the situation I explained
here?
Thanks in advance.
Regards,
Wouter Jorritsma
The Netherlands
I have a Windows 2000 Active Directory domain divided into 5 sites
which are connected with my main site through Win2K PPTP VPN. Each
site has it's own IP range. For example, site 1 has 192.168.1.x, site
2 has 192.168.2.x and so on.
I would like to implement a Win2K DHCP server in each site for my
laptop users, so they don't have to enter their IP addresses manually
when they go to another location of our company. In site 1, the DHCP
server has to provide IP addresses in the 192.168.1.x range, in site 2
it has to provide addresses in the 192.168.2.x range and so on.
Problem is that I don't want the DHCP server in site 1 to provide
addresses to clients in site 2 (through the VPN network, which is in
fact a transparent connection). The DHCP server must only be allowed
to give addresses to clients in it's own site. How do I make sure that
my concern won't happen? And is it possible to have more than one DHCP
server in 1 Active Directory domain, in the situation I explained
here?
Thanks in advance.
Regards,
Wouter Jorritsma
The Netherlands