CAST(? AS VARCHAR) + '%' ? represents variable. It does not work for empty variable. Still working on that one.
Rames wrote:
Sorry, I should have tried and asked the question here. It works same way!
12-Feb-08
Sorry, I should have tried and asked the question here. It works same way
selectCommand = "SELECT * FROM MR WHERE Name LIKE 'R%'
Thank
Rames
:
Previous Posts In This Thread:
Wildcard Character Placement in MS Query
I am attempting to establish a parameter in Excel containing a wildcard
before the prompt. I have successfully written it in access as: Like
"*"&[Enter City]) but cannot successfully accomplish it in MS Query. I am
currently entering the wildcard as part of the prompt response but this
limits me in other areas. Thank you for your help.
Re: Wildcard Character Placement in MS Query
Try this
Like '%' & [Enter City
Does that help
-------------------------
Regards
Ro
Microsoft MVP (Excel
(XL2003, Win XP)
Thanks for the suggestion.
Thanks for the suggestion. Unfortunately, I received the following error
message:
"Invalid operator for data type. Operator equals boolean AND, type equals
varchar. Statement(s) could not be prepared.
Any other ideas
:
I tested my posted LIKE clause using MS Query against an MS Access database.
I tested my posted LIKE clause using MS Query against an MS Access database
Are you querying another kind of database
Regards
Ro
Microsoft MVP (Excel
(XL2003, Win XP)
RE: Wildcard Character Placement in MS Query
Use % sign as wild card with single quotes eg : Like '%n' will return al
entries ending with
:
I'm using an SQL server database connected through ODBC to get data from the
I am using an SQL server database connected through ODBC to get data from th
tables
:
Does this work same way with Excel (as database) using OLE DB or ADO.NET?
Does this work same way with Excel (as database) using OLE DB or ADO.NET
I mean, can I use this wildcard charaters sameway when i am retrieving excel
data using OLE DB connection from VB.NET
Thanks for your response and time
Rames
:
Sorry, I should have tried and asked the question here. It works same way!
Sorry, I should have tried and asked the question here. It works same way
selectCommand = "SELECT * FROM MR WHERE Name LIKE 'R%'
Thank
Rames
:
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