V
VB Programmer
When I go from HTML view (in a webform) to Design View I get the following
error:
Could not open in Design view. Quote values differently inside a '<% ...
"value" ... %>' block.
I know exactly where it is. All I did was change the PARAM value of an
OBJECT from this:
<PARAM NAME="MyValue" VALUE="20">
to this:
<PARAM NAME="MyValue" VALUE="<% = Request.QueryString("Value1") %>">
The reason I changed the value is that I want the OBJECT to change it's
value, MyValue, based on what I send it in the querystring.
Any ideas? Better ways to do this?
Thanks,
Robert
error:
Could not open in Design view. Quote values differently inside a '<% ...
"value" ... %>' block.
I know exactly where it is. All I did was change the PARAM value of an
OBJECT from this:
<PARAM NAME="MyValue" VALUE="20">
to this:
<PARAM NAME="MyValue" VALUE="<% = Request.QueryString("Value1") %>">
The reason I changed the value is that I want the OBJECT to change it's
value, MyValue, based on what I send it in the querystring.
Any ideas? Better ways to do this?
Thanks,
Robert