M
MrDeveloper
First run sucess get data but reply call function (for get refresh data), i
get error.
what I am doing wrong in this code. I get error "The remote server returned
an error: (404) Not Found"
Thanks for helps...
Dim req As WebRequest
Dim rsp As WebResponse
Dim WebData() As String
Dim Temp() As String
Dim Str(2) As String
Dim myitm As ListViewItem
Dim i As Int16
Try
req = WebRequest.Create(http://www.zzz.com/demo.txt)
req.Method = "GET"
rsp = req.GetResponse()
Dim sr As New StreamReader(rsp.GetResponseStream())
WebData = Split(sr.ReadLine(), "-", -1, CompareMethod.Text)
Catch exp As Exception
' Will catch any error that we're not explicitly trapping.
MessageBox.Show(exp.Message)
Finally
Try
' Guarantee the streams will be closed
If Not rsp Is Nothing Then
rsp.GetResponseStream().Close()
End If
Catch ex As Exception
' Eat the error if we get one
MessageBox.Show(ex.Message)
End Try
End Try
get error.
what I am doing wrong in this code. I get error "The remote server returned
an error: (404) Not Found"
Thanks for helps...
Dim req As WebRequest
Dim rsp As WebResponse
Dim WebData() As String
Dim Temp() As String
Dim Str(2) As String
Dim myitm As ListViewItem
Dim i As Int16
Try
req = WebRequest.Create(http://www.zzz.com/demo.txt)
req.Method = "GET"
rsp = req.GetResponse()
Dim sr As New StreamReader(rsp.GetResponseStream())
WebData = Split(sr.ReadLine(), "-", -1, CompareMethod.Text)
Catch exp As Exception
' Will catch any error that we're not explicitly trapping.
MessageBox.Show(exp.Message)
Finally
Try
' Guarantee the streams will be closed
If Not rsp Is Nothing Then
rsp.GetResponseStream().Close()
End If
Catch ex As Exception
' Eat the error if we get one
MessageBox.Show(ex.Message)
End Try
End Try