THANKS FOR THE FANCY FORMULE Peo Sjoblom. IT WILL TAKE A LITTLE EFFORT TO
FIGURE IT OUT. This works nice for returning "12" which is one of the
problems I was trying to solve. I still have to deal with the negative issue.
I am currently using If statements which work fine but I have a feeling that
it isn't the most effecient method.
I am currently using:
b5 = -5555
=IF(B5=0,IF(C17=0, 0, IF(B5<0, "N.R.",VLOOKUP(B5,
StrapCapacity,2))),IF(B5<0, "N.R.",VLOOKUP(B5, StrapCapacity,2)))
This formula deals with the negative value
I feel that if this formula could deal with negatives it would look like this:
=VLOOKUP(B5, StrapCapacity,2)
much easier to manage
This is the result of your formul
=INDEX(Capacity,MATCH(SMALL(INDEX(Capacity,,1),COUNTIF(INDEX(Capacity,,1),"<"&ABS(B5))+1),INDEX(Capacity,,1),0),2)
=12
b5 = -5555
It should be
= 5
-10000	5
0	6
1000	7
2000	8
3000	9
4000	10
5000	11
6000	12
7000	13
8000	14
9000	15
Goes this make sense?