Urgent Help on converting vb6 chr$() to C#

  • Thread starter Thread starter Guest
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Guest

Dear all,

I'm using VB6 need to convert to C# for printing. In VB6 I will send some
printer command into the printer as below:-

Printer.Print "TESTING LINE 1"
Printer.Print "TESTING LINE 2"
Printer.Print Chr$(&H1C); "(L"; Chr$(66); Chr$(49);
Printer.Print Chr$(&H1D); "V"; Chr$(49);
Printer.Print Chr$(&H1C); "(L"; Chr$(67); Chr$(50);

In C# I'm writing a text file and open LPT1 to print some lines, the problem
is how to convert those VB6 codes into C# ?

I've try using some sample code as below :-

writer.WriteLine ("TESTING LINE 1" + ((char) 13));
writer.WriteLine ("TESTING LINE 2" + ((char) 13));
writer.WriteLine( ((char)&H1C) + "(L" + ((char)66) + ((char)49));

But there are errors on the above codes. Please provide solutions and
examples.

Thanks in advance


Cheers,
Mae
 
Mae Lim said:
I'm using VB6 need to convert to C# for printing. In VB6 I will send some
printer command into the printer as below:-

Printer.Print "TESTING LINE 1"
Printer.Print "TESTING LINE 2"
Printer.Print Chr$(&H1C); "(L"; Chr$(66); Chr$(49);
Printer.Print Chr$(&H1D); "V"; Chr$(49);
Printer.Print Chr$(&H1C); "(L"; Chr$(67); Chr$(50);

In C# I'm writing a text file and open LPT1 to print some lines, the problem
is how to convert those VB6 codes into C# ?

I've try using some sample code as below :-

writer.WriteLine ("TESTING LINE 1" + ((char) 13));
writer.WriteLine ("TESTING LINE 2" + ((char) 13));
writer.WriteLine( ((char)&H1C) + "(L" + ((char)66) + ((char)49));

But there are errors on the above codes. Please provide solutions and
examples.
Click to expand...

Well, the simplest way to get character 13 is just "\r". For hex, just
change &H to 0x, so &H1C is 0x1c, etc.
 
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