Start up Properties in Access 2002

  • Thread starter Thread starter Frank
  • Start date Start date
F

Frank

Hi All,

How do I set Startup properties through code in Access
2002? In Access 97 I was able to execute
currentdb.properties("StartUpShowDBWindow") = False

Now I get an error "Property not found"

Thanks,
 
Frank said:
Hi All,

How do I set Startup properties through code in Access
2002? In Access 97 I was able to execute
currentdb.properties("StartUpShowDBWindow") = False

Now I get an error "Property not found"

Works fine for me. You're not doing this in an ADP, are you?
 
That is not a default property. You need to create
a property with that name if you have not already
done so. For more information, read the Access help
or Google for "StartUpShowDBWindow".

(david)
 
david epsom dot com dot au said:
That is not a default property. You need to create
a property with that name if you have not already
done so. For more information, read the Access help
or Google for "StartUpShowDBWindow".

Oops, David's right; I'd forgotten about that. Frank, if this is a
database you also have manual access to, you can create the property
just by clicking Tools -> Startup, then modifying the "Display Database
Window" check box and clicking OK. But if you need to do this with
code, there are lots of examples previously posted, as David points out.
 
Thanks ! Works for me!

-----Original Message-----


Oops, David's right; I'd forgotten about that. Frank, if this is a
database you also have manual access to, you can create the property
just by clicking Tools -> Startup, then modifying the "Display Database
Window" check box and clicking OK. But if you need to do this with
code, there are lots of examples previously posted, as David points out.

--
Dirk Goldgar, MS Access MVP
www.datagnostics.com

(please reply to the newsgroup)


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