ShowDialog() problem

  • Thread starter Thread starter Mike
  • Start date Start date
M

Mike

Hi,

I want to show form as a modal dialog and use such code:
Dim frm_Zip As New frmZIP
frm_Zip.ShowDialog()

but instead of be as modal dialog, it is modeless - I can switch between forms.

Does anybody had the same problem?
OS: Win2000 Prof

Thanks
 
You need to specify the parent form in the ShowDialog call such as

frm_Zip.ShowDialog(Me)

to show as modal dialog for the current form
 
Hi,

I want to show form as a modal dialog and use such code:
Dim frm_Zip As New frmZIP
frm_Zip.ShowDialog()

but instead of be as modal dialog, it is modeless - I can switch between forms.

Does anybody had the same problem?
OS: Win2000 Prof

Thanks
Click to expand...

Strange. ShowDialog *does* create a modal dialog.

Are you calling this from a seperate thread?

// CHRIS
 
* (e-mail address removed) (Mike) scripsit:
I want to show form as a modal dialog and use such code:
Dim frm_Zip As New frmZIP
frm_Zip.ShowDialog()

but instead of be as modal dialog, it is modeless - I can switch between forms.

Does anybody had the same problem?
OS: Win2000 Prof
Click to expand...

Should work. Where do you use the code?
 
* "Scott said:
You need to specify the parent form in the ShowDialog call such as

frm_Zip.ShowDialog(Me)

to show as modal dialog for the current form
Click to expand...

Even calling it without specifying the form should show it modally.
 
Yes, the main form and dialog in different threads.

The scenario:

Main window create a new class and run it as a separate thread.
From that class I call ShowDialog.

Does it matter something? Because it is the same application , not separate
exe or dll module.

Thanks
 
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