M
Memnoch
Does anyone know of a way to get RA on Vista Business to only use port 3389 or
at least a static port rather than a completely random one?
You've probably guessed that this is a NAT related question. On my own network
I can get Vista and XP machines accepting and requesting RA without any
problems. But I have a friend of mine with both an XP and Vista machine behind
a router, set to forward port 3389. I can connect to his XP machine without
any problems because it uses port 3389. But on the Vista machine, the file
that is sent out uses a random port, such as below:
RCTICKET="65538,1,192.168.1.3:49682,"
You can't just change that port number as the program isn't listening on this
port.
This is a real pain and I can't find any information on this, and there is a
lot of BS floating around on Usenet too such as "XP machines can't accept
Vista RA requests", unless this was changed in SP1.
Any help with this would be much appreciated. I can't expect my friend to keep
opening random ports on his firewall to let me in, or al least modify the
existing rule.
Howard
at least a static port rather than a completely random one?
You've probably guessed that this is a NAT related question. On my own network
I can get Vista and XP machines accepting and requesting RA without any
problems. But I have a friend of mine with both an XP and Vista machine behind
a router, set to forward port 3389. I can connect to his XP machine without
any problems because it uses port 3389. But on the Vista machine, the file
that is sent out uses a random port, such as below:
RCTICKET="65538,1,192.168.1.3:49682,"
You can't just change that port number as the program isn't listening on this
port.
This is a real pain and I can't find any information on this, and there is a
lot of BS floating around on Usenet too such as "XP machines can't accept
Vista RA requests", unless this was changed in SP1.
Any help with this would be much appreciated. I can't expect my friend to keep
opening random ports on his firewall to let me in, or al least modify the
existing rule.
Howard