Reflection questions

[Martin Bischoff]

Hi,
if I have two classes, ClassA and ClassB, and ClassA has a member of
type ClassB, is it possible from within ClassB to find out that the
current instance is a member of ClassA?


Example:

class ClassA
{
private ClassB _myClassB = new ClassB();
}

class ClassB
{
public void FindOwner()
{
// is there some way to find out, that this
// instance is a member of an instance of
// ClassA, e.g. using reflection?
}
}


Thanks,
Martin

 

[Barry Kelly]

if I have two classes, ClassA and ClassB, and ClassA has a member of
type ClassB, is it possible from within ClassB to find out that the
current instance is a member of ClassA?

No, not without a manual brute-force search of the managed object heap.

-- Barry

 

[Kevin Yu [MSFT]]

Hi Martin,

I agree with Barry, that we can only see a parent has a certain child. But
we cannot check which parent a child belongs to in a very simple method. As
Barry mentioned, only with a brute-force search, can we get the parent of
certain child.

Kevin Yu
Microsoft Online Community Support

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[Adam Benson]

Errrr.... forgive me if this is a dumb question, but if an object must know
who created it, why not force anything creating that object to supply a
this, i.e. :

class ClassA
{
private ClassB _myClassB;
public ClassA()
{
_myClassB = new ClassB(this);
}
}

class ClassB
{
private object parent;
public ClassB(object daddy)
{
this.parent = daddy
}

public void FindOwner()
{
// Get the info from this.parent
}
}

HTH,

Adam.
==========

 

[Kevin Yu [MSFT]]

Hi Martin,

I'd like to know if this issue has been resolved yet. Is there anything
that I can help. I'm still monitoring on it. If you have any questions,
please feel free to post them in the community.

Kevin Yu
Microsoft Online Community Support

==================================================

(This posting is provided "AS IS", with no warranties, and confers no
rights.)

 

[Guest]

Thanks to everybody for the information. I will think about another solution
for my problem.

Best regards,
Martin

 

[Kevin Yu [MSFT]]

You're welcome, Martin. Please feel free to post in the communtiy if you
need any help.

Kevin Yu
Microsoft Online Community Support

==================================================

(This posting is provided "AS IS", with no warranties, and confers no
rights.)