I
Ian Lazarus
Hello,
If a function arg is a reference to a built in type, is it necessary for the
function definition to specify whether the reference is to a managed or
un-managed object? If so, does that mean that there needs to be two
(otherwise duplicate) functions in order for both types of objects to be
processed? E.g.,
void foo(int __gc & x);
void foo(int __nogc & x);
Thanks
If a function arg is a reference to a built in type, is it necessary for the
function definition to specify whether the reference is to a managed or
un-managed object? If so, does that mean that there needs to be two
(otherwise duplicate) functions in order for both types of objects to be
processed? E.g.,
void foo(int __gc & x);
void foo(int __nogc & x);
Thanks