-----Original Message-----
Thank you for the reply.
I will try this and let you know.
Thank you again for your help
Reed
-----Original Message-----
Open a new form in design view. Place a label near the
top that says what to do. Place 2
text boxes on the form, one for length and one for
quantity. Put a command button on the
form, set its Enabled property to No.
In the AfterUpdate event of each textbox, check to see
if
there is a valid value in each
textbox. If there is, set the Enabled property of the
button to Yes. In the OnClick event
of the button you would use something similar to:
TestRandomEntries Me.txtTextbox1, Me.txtTextbox2
This will put the entries into the table. What you do
from here is up to you. Also, you
didn't say if you wanted the table cleared before each
time you create entries. At the
moment, it is not being cleared. The new entries are added after the previous ones.
--
Wayne Morgan
Microsoft Access MVP
Reed said:
So how would I create the form to put in the values of Qty
and Length? I assume that the code below would attach to a
form event.
Thank you
Reed
-----Original Message-----
This appears to do what you ask. You would call it with
the 2 parameters you asked for.
Example:
TestRandomEntries 10, 10
will give 10 entries that are 10 characters long.
Public Sub TestRandomEntries(intQty As Integer, intLength
As Integer)
On Error GoTo HandleError
Dim intValue As Integer, strValue As String, intCount As
Integer
Dim db As DAO.Database, rst As DAO.Recordset
Set db = CurrentDb
Set rst = db.OpenRecordset("Table9", dbOpenTable)
Randomize
Const DUPLICATE_INDEX = 3022
intCount = 0
strValue = ""
Do Until intCount = intQty
Do Until Len(strValue) = intLength
'Alpha Numeric characters are ASCII 48-57, 65- 90,
and 97-122
'Formula from the help file
'Int((upperbound - lowerbound + 1) * Rnd +
lowerbound)
intValue = Int((122 - 48 + 1) * Rnd + 48)
Select Case intValue
Case 48 To 57, 65 To 90, 97 To 122
strValue = strValue & Chr(intValue)
Case Else
End Select
Loop
With rst
.AddNew
![fldNumbers] = strValue 'Add data.
.Update 'Save changes.
End With
'Increment our counter to see
'how many we have added
intCount = intCount + 1
'Start a new string
strValue = ""
Loop
CleanUp:
On Error Resume Next
rst.Close
Set rst = Nothing
Set db = Nothing
Exit Sub
HandleError:
If Err.Number = DUPLICATE_INDEX Then
'Only count successful additions
intCount = intCount - 1
Resume Next
End If
MsgBox Err.Number & vbCrLf & Err.Description, , "Error"
Resume CleanUp
End Sub
--
Wayne Morgan
Microsoft Access MVP
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