G
gswin
What is the difference between the following:
a. x = 2% 2 + 2 * 2 - 2/2
b. x = (2 % 2 + 2) * 2 - 2/2
Thnx.
a. x = 2% 2 + 2 * 2 - 2/2
b. x = (2 % 2 + 2) * 2 - 2/2
Thnx.
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V
Vijayakrishna Pondala
a. The value of x will be:
x = (2%2) + (2*2) - (2/2)
= 0 + 4 - 1
= 3
b. The value of x in this case will be:
x = ((2%2) + 2)*2 - (2/2)
= (0+2)*2 - (2/2)
= 4-1
= 3.
Though the values of x in the above cases are same, there is a difference in
the order/precedence in which the expressions are evaluated. Try with
different numbers like
1%2+3*4-5/2 and (1%2+3)*4 - 5/2, where the values differ.
Refer: Operator precedence
Thanks
VijayaKrishna P.
x = (2%2) + (2*2) - (2/2)
= 0 + 4 - 1
= 3
b. The value of x in this case will be:
x = ((2%2) + 2)*2 - (2/2)
= (0+2)*2 - (2/2)
= 4-1
= 3.
Though the values of x in the above cases are same, there is a difference in
the order/precedence in which the expressions are evaluated. Try with
different numbers like
1%2+3*4-5/2 and (1%2+3)*4 - 5/2, where the values differ.
Refer: Operator precedence
Thanks
VijayaKrishna P.
G
gswin
THANK YOU!
-----Original Message-----
a. The value of x will be:
x = (2%2) + (2*2) - (2/2)
= 0 + 4 - 1
= 3
b. The value of x in this case will be:
x = ((2%2) + 2)*2 - (2/2)
= (0+2)*2 - (2/2)
= 4-1
= 3.
Though the values of x in the above cases are same, there is a difference in
the order/precedence in which the expressions are evaluated. Try with
different numbers like
1%2+3*4-5/2 and (1%2+3)*4 - 5/2, where the values differ.
Refer: Operator precedence
Thanks
VijayaKrishna P.
.