"Paul" said:
Hey Paul!
Yes - I have just calculated I need 532 watts, with 5 Drives! Blimey I'm
right on the edge with the Antec 550. I removed my Q-Tec 550 watt psu last
night and the label quotes: - 16A Max and 20A Peak on the +12v rail - what
"did" this mean?
TA
Paul (Rozel)
Thanks gawderho
Not every estimate on the jscustompcs site is golden. For disk drive
estimates, for example, remember to get the info directly from the
disk drive manufacturer, as they do give numbers. The jscustompcs
site uses the peak startup current, and the drives don't stay at
that level for more than 10 or 15 seconds or so. As I said in a previous
post, if you have five drives, four will be idle at any one time,
and their consumption could be 7-10 watts when idle (consult manufacturer
numbers for more accuracy). Since the spindles are all stably spinning
at rated speed, the drive motors only have to make up from frictional
losses. So, to start, you can knock about 75 Watts off that number.
In a way, that relates to the purpose of the 16A Max and 20A Peak
numbers. The Max number is for continuous consumption, after the
computer has booted. The 20A Peak number applies for the time it
takes the disk drives to spin up. Basically, the peak time is limited
by the time it takes to overheat the components inside the PS,
so the more massive the heatsinks inside it, the longer the PS
can take the Peak number.
Another glaring error on the jcscustompcs site, is they are
calculating the "input power" - this is the power drawn from
the wall. They are including the inefficiency of the power
supply itself - the power supply generates waste heat when it
is making the output voltages. But the rating of the power
supply itself, is in terms of its outputs, not its inputs. So
the jcscustompcs site is overestimating the whole consumption
number by 20%. As a result, even with gross overestimation,
you won't be over 400 watts of PS output power. (You have to
remember that JCS makes more money by selling big power supplies!)
Processor 1.5V Vcore Conversion 12V AC-DC Conversion Wall
81.8 Watts ------ 80% efficient -------- 70%-80% efficient --- Power
81.8/12=6.8A ^ 12*8.5=102.3W ^
6.8/0.80=8.5A _/ 102.3W/0.70=146W_/
The JCS site is working out the wall power, whereas the PS is
actually rated in terms of the number in the center of the
picture above, which is the power provided to the motherboard.
That 550W is plenty for your system. In fact, a 550W is typically
used for dual processor systems, so you've got at least another
processor's worth of capacity. (Don't forget to include the power
used for your water cooling system, as JCS won't include that.)
Paul