Please help - considering IP address translation

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G

Guest

Hello!
How to solve such question!
If I have IP address 136.28.86.63. How do I know how much leftmost bits I have in that address to calculate subnet mask I should use?
136.28.86.63 in binary looks like that:
10001000.00011100.01010110.00111111
Could someone explain how much leftmost bits are in common in that address? My system administrator told, that there is 20 leftmost bits in common(so i should use 20 bit subnet mask). Explain please.

Regards,

C.
 
C said:
Hello!
How to solve such question!
If I have IP address 136.28.86.63. How do I know how much leftmost bits I
have in that address to calculate subnet mask I should use?
136.28.86.63 in binary looks like that:
10001000.00011100.01010110.00111111
Could someone explain how much leftmost bits are in common in that
address? My system administrator told, that there is 20 leftmost bits in
common(so i should use 20 bit subnet mask). Explain please.
Regards,

C.

The subnet mask determines which IP addresses are considered inside
addresses, and which ones are not. To answer your question, one would need
to know what other subnet(s) you have in your place. Without this
information, your question is equivalent to asking "Which is longer, the
distance from Boston to Denver?".

The most often used subnet mask allows for every address from 136.28.86.1 to
136.28.86.254 to be treated as an "inside" address. It consists of 24 "1"s
(255.255.255.0 = 11111111.11111111.1111111.00000000), because the only
allowed variation is the the last group of digits.
 
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