Parsing a string

[Mike Kanski]

Here's an expample:

dim s as string
s=""c:\blah blah\"" ""c:\koko\"" ""c:\booo boo\""
console.write ubound(s.split(""" """))

result of ubound is 3
Should be 2 !

What i'm trying to do is to say that the delimeter in the string is DOUBLE
QUOTE SPACE DOUBLE QUOTE (" ")
And Split still counts all the spaces!
Any suggestions?

 

[Wim Hollebrandse]

The UBound simply gives you the count of the result array, being split by your " ".

If you sawed a log into three pieces, you'd have to saw it twice.



Cheers,
Wim Hollebrandse
http://www.wimdows.net
http://www.wimdows.com

 

[Jerry III]

Isn't this because VB arrays are 1 based? So your split will give you an
array with 1, 2 and 3 indexes, so the ubound is 3 and lbound is going to be
1. I think this is the expected behavior in VB.

Jerry