F
Flasherly
I'm building a knife sharpener with a 25-deg angle out of ceramic
hollow rods. Ceramic stock: 4-1/2" long & 3/8" diameter.
Right Angle Triangle: the two sides at 90-deg, one of which will be,
of course, the base.
Figure roughly around a 10" plug-in value for an extended "sharpening
edge," which will also be the same as the 3rd side of the triangle.
(I'll rig the ceramic rods to that 10" via the hollow center, with a
steel rod, or a wooden frame that clamps down. Figure that out
later.)
Anyway, I just need the math. If the opposite, 10" side to the right
triangle forms a 25-deg. angle, (to the two other, 90-degree sides),
sic. -- a 25-deg. angle, that is, to the straight-edge of a knife
being sharpened perpendicularly to the base of the triangle -- give me
the measurements for the two remaining triangular lengths to an
approximate 10" third side I've proposed.
Avoid decimal fractions of an inch (I've a precision steel ruler
that'll go up to 64th or 128ths. Actually, I'll be doing it twice
with two ceramic rods and bringing them together for sharpening both
sides of my cutlery simultaneously.)
Hell the whole damn thing could be made adjustable, compact and
secure, for a 15- to 35-degree leeway varying from finer knives to
hatchets and cleavers. Where's all the whizbang, latenite TeeVee
copyright holders when you've got a perfectly good handle on a
copyright scheme and need them?
hollow rods. Ceramic stock: 4-1/2" long & 3/8" diameter.
Right Angle Triangle: the two sides at 90-deg, one of which will be,
of course, the base.
Figure roughly around a 10" plug-in value for an extended "sharpening
edge," which will also be the same as the 3rd side of the triangle.
(I'll rig the ceramic rods to that 10" via the hollow center, with a
steel rod, or a wooden frame that clamps down. Figure that out
later.)
Anyway, I just need the math. If the opposite, 10" side to the right
triangle forms a 25-deg. angle, (to the two other, 90-degree sides),
sic. -- a 25-deg. angle, that is, to the straight-edge of a knife
being sharpened perpendicularly to the base of the triangle -- give me
the measurements for the two remaining triangular lengths to an
approximate 10" third side I've proposed.
Avoid decimal fractions of an inch (I've a precision steel ruler
that'll go up to 64th or 128ths. Actually, I'll be doing it twice
with two ceramic rods and bringing them together for sharpening both
sides of my cutlery simultaneously.)
Hell the whole damn thing could be made adjustable, compact and
secure, for a 15- to 35-degree leeway varying from finer knives to
hatchets and cleavers. Where's all the whizbang, latenite TeeVee
copyright holders when you've got a perfectly good handle on a
copyright scheme and need them?