T
Tom
How can I make code not execute for a debug build, but do
execute for a production build?
I have code which prompts for an account and password when
the program starts up. It is a pain to have to answer that
when I repeatly run the program during debugging, but it
is desired by my client. Presently I just comment it out
when I am debugging, but I was wondering if there was a
more automatic way? Some type of conditional compilation
depending on the type of build?
On another note, I'd like to say that since I started
programming VB 6 weeks ago I have found this forum
incredibly useful. I've learned not only from the answers
to my questions but from others questions as well. I'd
like to thank the several of you who answer most of the
questions. It is incredibly helpful. You must put a lot
of time into it and it is incredibly useful as the
Microsoft documentation is so poor. Just out of
curisosity, what motivates you to put so much time into
helping people on this forum and what does the "MVP"
several of you have after your names mean?
Thanks,
Tom
execute for a production build?
I have code which prompts for an account and password when
the program starts up. It is a pain to have to answer that
when I repeatly run the program during debugging, but it
is desired by my client. Presently I just comment it out
when I am debugging, but I was wondering if there was a
more automatic way? Some type of conditional compilation
depending on the type of build?
On another note, I'd like to say that since I started
programming VB 6 weeks ago I have found this forum
incredibly useful. I've learned not only from the answers
to my questions but from others questions as well. I'd
like to thank the several of you who answer most of the
questions. It is incredibly helpful. You must put a lot
of time into it and it is incredibly useful as the
Microsoft documentation is so poor. Just out of
curisosity, what motivates you to put so much time into
helping people on this forum and what does the "MVP"
several of you have after your names mean?
Thanks,
Tom