Log output of regsvr32 command.

  • Thread starter Thread starter Hetal
  • Start date Start date
H

Hetal

I have created a batch file that unregisters the old version of a dll,
copies the new version, and registers a new version of that dll on a
computer. The script works perfectly fine, but i would like to log the
output of this batch file to a text file.

I tried using the ">" redirector to create a file and the following
lines, i used ">>" redirector to append that file but the output from
regsvr32 does not log to the text file.

The bacth file that i created looks like this:
===============
@ECHO OFF
regsvr32 -u -s %windir%\System32\test.dll > C:\Test.txt
COPY \\server\sharedfolder\test.dll %windir%\System32\ >> C:\Test.txt
regsvr32 -s %windir%\System32\test.dll >> C:\Test.txt
===============

But the log file generated by this batch file only states:
===============
1 File(s) copied.
===============

Is there a way i can redirect the result of regsvr32 command to the
text file?

Thanks!!
 
Hetal said:
I have created a batch file that unregisters the old version of a dll,
copies the new version, and registers a new version of that dll on a
computer. The script works perfectly fine, but i would like to log the
output of this batch file to a text file.

I tried using the ">" redirector to create a file and the following
lines, i used ">>" redirector to append that file but the output from
regsvr32 does not log to the text file.

The bacth file that i created looks like this:
===============
@ECHO OFF
regsvr32 -u -s %windir%\System32\test.dll > C:\Test.txt
COPY \\server\sharedfolder\test.dll %windir%\System32\ >> C:\Test.txt
regsvr32 -s %windir%\System32\test.dll >> C:\Test.txt
===============

But the log file generated by this batch file only states:
===============
1 File(s) copied.
===============

Is there a way i can redirect the result of regsvr32 command to the
text file?

Thanks!!
Click to expand...

As far as I know, all output from regsvr32.exe is directed
to a dialog box (which you suppress with the -s switch), and
none to the console where it could be captured.
 
Hi Pegasus.

Thank you for your response. Based on your inputs, it seems as if
there is no way to direct the result of regsvr32 to a log/text file.
The objective i am trying to achieve here is, i am deploying a newer
version of dll at domain level and i need to make sure that all
computers under that domain got updated.

I am not sure if the path that i have chosen to track this update is
efficient, but i would like to know if there is a better way to
achieve my objective?

Thanks.
 
Hetal said:
Hi Pegasus.

Thank you for your response. Based on your inputs, it seems as if
there is no way to direct the result of regsvr32 to a log/text file.
The objective i am trying to achieve here is, i am deploying a newer
version of dll at domain level and i need to make sure that all
computers under that domain got updated.

I am not sure if the path that i have chosen to track this update is
efficient, but i would like to know if there is a better way to
achieve my objective?

Thanks.
Click to expand...

I suspect that the best you can do is to create a log of
the machines where you applied the regsvr command,
e.g. like so:
@echo off
echo %date% %time% regsvr #1 applied on %ComputerName# >>
\\YourServer\SomeShare\Logs\regsrv.log
(this is a single long line!)
 
I don't see your original post but I think you are looking for something
like this. If you want to test for success, use errorlevel 0 instead.
-----begin-----
@echo off
regsvr32 /s mydllfile.dll
if errorlevel 3 echo "this failed" >> c:\test.txt
-----end-----
Louis
 
I tried this before I gave my previous reply and found that
regsvr32 always returns an ErrorLevel of 0. Did you find
an instance when it does not? If so then please post it.
 
Now that I think about it, you should probably test for success (errorlevel
0) because there may be different exit codes for different failures and I
did not account for them. I actually put my batch file together by trial and
error.
Louis
 
This is very interesting. I should check more carefully before posting.
"regsvr32 invalid\path\to\file" and "regsvr32 path\to\invalid\dllfile" test
true for errorlevels 0, 1, 2, and 3. A successful registration tests true
for errorlevel 0 only. (As far as I know from limited testing.) Please post
back if you can explain this. From your previous posts, your knowledge of
batch files is much greater than mine, but I can usually hack something
together when I need it.
Louis
 
Here is a good way to test ErrorLevels:

regsvr32 invalid\path\to\file
echo Error Level=%ErrorLevel%
 
i was quizzed by this errorlevel thing too... i previously had below
statements in my batch file and when this piece of code used to
execute, it would always returns true even if dll registration fails.

=============
regsvr32 -u -s %windir%\System32\arview2.ocx
if ErrorLevel 0 echo "registered myfile.dll" >> c:\test.log
=============

I researched a bit online and figured that the "If" condition in line
2 above interprets as ErrorLevel >=0 instead of ErrorLevel = 0. So
even if regsvr32 return error code 2, the condition ErrorLevel >=0
satisfies and return true.

i changed the second line of my code as mentioned below and that
worked for me.
=============
if %ErrorLevel% NEQ 0 echo "failed registered myfile.dll" >> c:
\test.log
=============

Please refer the following link for further information on ErrorLevel.
I got all the information regarding errorlevel from this website.

http://www.robvanderwoude.com/errorlevel.html

Thanks,
Hetal.
 
I was quizzed by this errorlevel thing too... i previously had below
statements in my batch file and when this piece of code used to
execute, it would always return true even if dll registration failed.

=============
regsvr32 -u -s %windir%\System32\arview2.ocx
if ErrorLevel 0 echo "registered myfile.dll" >> c:\test.log
=============

I researched a bit online and figured that the "If" condition in line
2 above interprets as ErrorLevel >=0 instead of ErrorLevel = 0. So if
regsvr32 return error code 2, the condition ErrorLevel >=0 is
satisfied and it returns true.

i changed the second line of my code as mentioned below and that
worked for me.
=============
if %ErrorLevel% NEQ 0 echo "failed registered myfile.dll" >> c:
\test.log
=============

Please refer the following link for further information on ErrorLevel.
I got information needed by me on ErrorLevel from this website.

http://www.robvanderwoude.com/errorlevel.html

Thanks,
Hetal.
 
*** See below.

Hetal said:
i was quizzed by this errorlevel thing too... i previously had below
statements in my batch file and when this piece of code used to
execute, it would always returns true even if dll registration fails.

=============
regsvr32 -u -s %windir%\System32\arview2.ocx
if ErrorLevel 0 echo "registered myfile.dll" >> c:\test.log
=============

I researched a bit online and figured that the "If" condition in line
2 above interprets as ErrorLevel >=0 instead of ErrorLevel = 0.
Click to expand...

*** This is correct.
So even if regsvr32 return error code 2, the condition ErrorLevel
Click to expand...

*** Yes.
i changed the second line of my code as mentioned below and that
worked for me.
=============
if %ErrorLevel% NEQ 0 echo "failed registered myfile.dll" >> c:
\test.log
=============
Click to expand...

*** You are now using a completely different approach. Your
*** initial approach was based on the statement
*** "if ErrorLevel" (without %!), which is a legacy DOS method.
*** Your current statement uses the environmental variable
*** %ErrorLevel%, which was introduced with WinNT or
*** perhaps with Win2000.
*** You could also write
*** if %ErrorLevel% GTR 0 or
*** if %ErrorLevel% GEQ 1
*** Use "if /?" to see the possible conditions for "if".
 
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