Linq60

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AA2e72E

At this site: http://msdn.microsoft.com/en-us/vcsharp/aa336746.aspx
The example : First - Indexed

This sample prints the elements of an integer array that are both even and
at an even index within the array. It uses First with an index parameter to
find the desired numbers.

public void Linq60() {
int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

int evenNum = numbers.First((num, index) => (num % 2 == 0) && (index % 2
== 0));

Console.WriteLine("{0} is an even number at an even position within the
list.", evenNum);
}

The line int evenNum = numbers.First((num, index) => (num % 2 == 0) &&
(index % 2 == 0));

Creates an error : Delegate 'System.Func<int,bool>' does not take '2'
arguments

How can I alter the offending line (still using LINQ) to reproduce the
result shown?

PS: !!! I don't understand the point of publishing samples that do NOT work-
there are several others like this at the site !!!
 
AA2e72E said:
At this site: http://msdn.microsoft.com/en-us/vcsharp/aa336746.aspx
The example : First - Indexed

This sample prints the elements of an integer array that are both even and
at an even index within the array. It uses First with an index parameter to
find the desired numbers.

public void Linq60() {
int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

int evenNum = numbers.First((num, index) => (num % 2 == 0) && (index % 2
== 0));

Console.WriteLine("{0} is an even number at an even position within the
list.", evenNum);
}

The line int evenNum = numbers.First((num, index) => (num % 2 == 0) &&
(index % 2 == 0));

Creates an error : Delegate 'System.Func<int,bool>' does not take '2'
arguments

How can I alter the offending line (still using LINQ) to reproduce the
result shown?

PS: !!! I don't understand the point of publishing samples that do NOT work-
there are several others like this at the site !!!
Click to expand...

I don't know why the example is in there, there is no overload of the
First method that uses a delegate with an index. As the page is under
"future versions", perhaps the method had such an overload at a stage in
the development.

You can use Where and First to make the code work, but that's not really
the point of the example...

int evenNum = numbers.Where((num, index) => (num % 2 == 0) && (index % 2
 
Thanks for the solution

int evenNum = numbers.Where((num, index) => (num % 2 == 0) && (index % 2
== 0)).First();

Note: there is a stray > on the continuation line of the above post that
should not be there.
Göran Andersson said:
AA2e72E said:
At this site: http://msdn.microsoft.com/en-us/vcsharp/aa336746.aspx
The example : First - Indexed

This sample prints the elements of an integer array that are both even and
at an even index within the array. It uses First with an index parameter to
find the desired numbers.

public void Linq60() {
int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

int evenNum = numbers.First((num, index) => (num % 2 == 0) && (index % 2
== 0));

Console.WriteLine("{0} is an even number at an even position within the
list.", evenNum);
}

The line int evenNum = numbers.First((num, index) => (num % 2 == 0) &&
(index % 2 == 0));

Creates an error : Delegate 'System.Func<int,bool>' does not take '2'
arguments

How can I alter the offending line (still using LINQ) to reproduce the
result shown?

PS: !!! I don't understand the point of publishing samples that do NOT work-
there are several others like this at the site !!!
Click to expand...

I don't know why the example is in there, there is no overload of the
First method that uses a delegate with an index. As the page is under
"future versions", perhaps the method had such an overload at a stage in
the development.

You can use Where and First to make the code work, but that's not really
the point of the example...

int evenNum = numbers.Where((num, index) => (num % 2 == 0) && (index % 2
== 0)).First();
Click to expand...
Click to expand...
 
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