J
javaguy
On my laptop (2.5 GB RAM) the Task Manager says that memory usage is
800MB. Sometimes more, sometimes less, depending on other programs
running.
I'm aware that Vista is supposed to be caching things and such, but I
haven't found a discussion about how much memory Vista needs all by
itself.
For example, an XP computer with similar configuration (same brand
anti-virus, fairly clean of little system-tray programs) might take
180MB of RAM, according to XP's Task Manager. So when Vista's Task
Manager says it is using 800MB for a similar condition, does that mean
that Vista is 600MB piggier just to make the computer work? Or does
that mean something like 400MB to make the computer work and 400MB for
stuff like SuperFetch?
Suppose I start a memory-intensive program like a spreadsheet
program. Will all of the memory for that new program come from
currently unused memory, or is some (a lot) obtained from the
previously grabbed 800MB?
As a side issue, if Vista is caching memory, then why doesn't it cache
all 2GB of RAM instead of a fraction?
Thanks in advance,
Jerome.
800MB. Sometimes more, sometimes less, depending on other programs
running.
I'm aware that Vista is supposed to be caching things and such, but I
haven't found a discussion about how much memory Vista needs all by
itself.
For example, an XP computer with similar configuration (same brand
anti-virus, fairly clean of little system-tray programs) might take
180MB of RAM, according to XP's Task Manager. So when Vista's Task
Manager says it is using 800MB for a similar condition, does that mean
that Vista is 600MB piggier just to make the computer work? Or does
that mean something like 400MB to make the computer work and 400MB for
stuff like SuperFetch?
Suppose I start a memory-intensive program like a spreadsheet
program. Will all of the memory for that new program come from
currently unused memory, or is some (a lot) obtained from the
previously grabbed 800MB?
As a side issue, if Vista is caching memory, then why doesn't it cache
all 2GB of RAM instead of a fraction?
Thanks in advance,
Jerome.