Now the serious response.
Saar said:
This assignment, if you had read it, isn't about an
amortization of a loan. It's about putting in payments
and accumulating $75,000. The payment put into the
beginning of the period WILL ABSOLUTELY HAVE EARNED
INTEREST BY THE END OF THE FIRST PERIOD and must be
credited to the account to start the second period payment.
True, if a payment is made at the beginning of a period, interest should
accrue by the end of that period. However, there's at best some ambiguity
here. Where does it say that the interest accrued for a given period
wouldn't be measured as of the time of that period's payment? If there's no
initial balance (PV arg zero/missing) but payments made at the beginning of
each period, then the interest accrued at the time of the first payment is
correctly zero. If payments are made at the end of each period, then again
with no initial balance the interest accrued in the fist period at the time
of the first payment is also zero.
Given the specs in the other thread in which you failed to respond, the
constant monthly payment was 182.68. Payments were made at the beginning of
each period. The balance accruing interest during the first period is just
the first payment, so interest accrued at the end of the first period is
0.99. What does
IPMT(0.065/12,2,216,,-75000,1)
return? Given one possible set of semantics for the final argument, this
means the interest accrued as of the beginning of the second period is the
same as the interest accrued as of the end of the first period.
If IPMT has a flaw, it's that it doesn't return
IPMT(r,n,n,,-FV,1)*((1+r)^k-1)
for
IPMT(r,n+k,n,,-FV,1) for k > 0. However, I can see why Microsoft made IPMT
return errors when IPMT's second arg falls outside the range [1;NPER].
Learn what is going on before jumping to conclusions. So
much for MVP's all jumping on the bandwagon without
knowing what it's all about.
Oh, it's not just the MVPs. Many people know how to cope with Excel. You
should try to do so yourself.
I dare any of you to put the formula through IPMT with a
payment of $182.68, (which is computed through the PMT
function), show an interest rate of 6.5% annually, over 18
years, first payment made at the beginning of the period;
run a spreadsheet showing the accumulation of monies for
that time period, and come up with $75,000 on the 216th
period. With IPMT it WON'T happen. You can't get the
&75,000 unless you put in your own formula and not IPMT.
A challenge!
For my one ease, I'll use defined names i referring to =0.065/12, NPer
referring to =18*12, and FV referring to =75000.
A1:
=ROW()
B1:
=PMT(i,NPer,,-FV,1)
C1:
=IPMT(i,A1,NPer,PMT(i,NPer,,FV,1),FV-PMT(i,NPer,,FV,1),0)
D1:
=SUM(B$1:C1)
Fill A1
1 down into A2
216. What do you get in cell D216?
I already gave you the C1 formula above in my initial response to your rant.
A pity you didn't test it before you set out to prove just how obtuse you
can be.
I took all of your MVP answers to two (2) count them (2)
certified Microsoft Instructors at the local University
and had them run the IPMT function. IT DOESN'T WORK on a
accumulation of money.
Got names? Got any proof? Got any wit?
Ah, but there's that unfortunate presumption that certification equals
knowledge again. How many certified Microsoft Instructors answer newsgroup
postings?
No matter. I refuse to assume that these claimed certified instructors
failed to use IPMT to reach the correct answer for any reason other than the
poor job you very likely did in posing the problem to them.
But it just doesn't matter. All that matters is demonstrated in the formulas
above. Learn from them or not.