how to write embeded if statement

  • Thread starter Thread starter thinktwice
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thinktwice

i have written something like:
if not (%1) == () (
if not %1 == "" (set SENDER=%1))

but it doesn't work, it's invalid if statement
 
i have written something like:
if not (%1) == () (
if not %1 == "" (set SENDER=%1))

but it doesn't work, it's invalid if statement
Click to expand...

This one is tricky - it took a minute to figure out. Even though it
appears that the blank condition of the replaceable parameter, %1, is
being tested; the syntax of the second part of your compound statement
is being parsed, anyway. This is because the command processor is a
single pass processor and the parentheses make the multiple lines a
single statement (all of which is evaluated at one time). Therefore,
if %1 is empty, a syntax error results.

Try something like this ...

if not (%1) == () (
if not [%1] == [""] (set SENDER=%1))

Tom Lavedas
===========
http://members.cox.net/tglbatch/wsh/
 
thinktwice said:
i have written something like:
if not (%1) == () (
if not %1 == "" (set SENDER=%1))

but it doesn't work, it's invalid if statement
Click to expand...

What are you trying to determine by the condition?

.... I can guess of course, but I'd like to make sure I'm not incorrectly
inferring your goal.
 
i have written something like:
if not (%1) == () (
if not %1 == "" (set SENDER=%1))
Click to expand...
but it doesn't work, it's invalid if statement
Click to expand...

What are you trying to determine by the condition?

... I can guess of course, but I'd like to make sure I'm not incorrectly
inferring your goal.

--
Dean Wells [MVP / Directory Services]
MSEtechnology
[[ Please respond to the Newsgroup only regarding posts ]]
R e m o v e t h e m a s k t o s e n d e m a i l
Click to expand...

thanks for you help, i'm trying to make sure the parameter that passed
to my batch file isn't empty nor ""
 
i have written something like:
if not (%1) == () (
if not %1 == "" (set SENDER=%1))
Click to expand...
but it doesn't work, it's invalid if statement
Click to expand...

What are you trying to determine by the condition?

... I can guess of course, but I'd like to make sure I'm not incorrectly
inferring your goal.

--
Dean Wells [MVP / Directory Services]
MSEtechnology
[[ Please respond to the Newsgroup only regarding posts ]]
R e m o v e t h e m a s k t o s e n d e m a i l
Click to expand...

thanks for you help, i'm trying to make sure the parameter that passed
to my batch file isn't empty nor ""

try this, then:

if "%~1" EQU "" (
echo/first parameter is either empty (null, missing) or ""
) else (
echo/an actual non-null value was passed as the first parameter.
)

This can sometimes be useful too:

(set _param=%~1)
if defined _param (
echo/an actual non-null value was passed as the first parameter.
) else (
echo/first parameter is either empty (null, missing) or ""
)

/Al
 
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