How to use VB Express to run a program through command promptinterface?

  • Thread starter Thread starter Sooraj
  • Start date Start date
S

Sooraj

Hi,
I'm a mechanical engineer new to programming. I was trying to write a
program in Visual Basic Express Edition 2005. I want to run a file
using an application called madymo601 in command prompt.

Normally what I do is to go to Start> Run> and type cmd /k madymo601 c:
\filename.xml . I have put the /k there as i need the cmd window open
after execution to view the results. I tried to make a small VB
program to avoid typing in the commands since the .xml files I need to
run could be in various locations. I wrote a code as given below. But
seems to have something wrong with the diagnostics.process.start line.


Private Sub Button1_Click(ByVal sender As Object, ByVal e As
System.EventArgs) Handles Button1.Click
OpenFileDialog1.Title = "Please select .xml file"
OpenFileDialog1.Filter = "xml files|*.xml"
OpenFileDialog1.ShowDialog()
If OpenFileDialog1.FileName <> "" Then

TextBox1.Text = (OpenFileDialog1.FileName)
End If
End Sub

Private Sub Button2_Click(ByVal sender As Object, ByVal e As
System.EventArgs) Handles Button2.Click
Dim filepath As String = (TextBox1.Text)

Diagnostics.Process.Start("cmd /k madymo601", filepath)
End Sub

Hope someone could help me out with the right way to do this.
Thanx.
 
Hi,
I'm a mechanical engineer new to programming. I was trying to write a
program in Visual Basic Express Edition 2005. I want to run a file
using an application called madymo601 in command prompt.

Normally what I do is to go to Start> Run> and type cmd /k madymo601 c:
\filename.xml . I have put the /k there as i need the cmd window open
after execution to view the results. I tried to make a small VB
program to avoid typing in the commands since the .xml files I need to
run could be in various locations. I wrote a code as given below. But
seems to have something wrong with the diagnostics.process.start line.

Private Sub Button1_Click(ByVal sender As Object, ByVal e As
System.EventArgs) Handles Button1.Click
OpenFileDialog1.Title = "Please select .xml file"
OpenFileDialog1.Filter = "xml files|*.xml"
OpenFileDialog1.ShowDialog()
If OpenFileDialog1.FileName <> "" Then

TextBox1.Text = (OpenFileDialog1.FileName)
End If
End Sub

Private Sub Button2_Click(ByVal sender As Object, ByVal e As
System.EventArgs) Handles Button2.Click
Dim filepath As String = (TextBox1.Text)

Diagnostics.Process.Start("cmd /k madymo601", filepath)
End Sub

Hope someone could help me out with the right way to do this.
Thanx.
Click to expand...

Hi Sooraj,
To use Command prompt, you'd better use Shell instead of Process
class[Process class wants exact path of cmd.exe(c:\windows
\system32\cmd.exe..... unlike Shell)].

So, it would be like this:
Shell("cmd /k madymo601 filepath",AppWinStyle.NormalFocus)

And make sure you include exact path of your application to launch. I
mean, for example if you application (madymo601) resides as c:
\madymo601.exe then you should use:

Shell("cmd /k c:\madymo601 filepath",AppWinStyle.NormalFocus)

Hope this helps,

Onur Güzel
 
Hi,
I'm a mechanical engineer new to programming. I was trying to write a
program in Visual Basic Express Edition 2005. I want to run a file
using an application called madymo601 in command prompt.
Click to expand...
Normally what I do is to go to Start> Run> and type cmd /k madymo601 c:
\filename.xml . I have put the /k there as i need the cmd window open
after execution to view the results. I tried to make a small VB
program to avoid typing in the commands since the .xml files I need to
run could be in various locations. I wrote a code as given below. But
seems to have something wrong with the diagnostics.process.start line.
Click to expand...
Private Sub Button1_Click(ByVal sender As Object, ByVal e As
System.EventArgs) Handles Button1.Click
OpenFileDialog1.Title = "Please select .xml file"
OpenFileDialog1.Filter = "xml files|*.xml"
OpenFileDialog1.ShowDialog()
If OpenFileDialog1.FileName <> "" Then
Click to expand...
TextBox1.Text = (OpenFileDialog1.FileName)
End If
End Sub
Click to expand...
Private Sub Button2_Click(ByVal sender As Object, ByVal e As
System.EventArgs) Handles Button2.Click
Dim filepath As String = (TextBox1.Text)
Click to expand...
Diagnostics.Process.Start("cmd /k madymo601", filepath)
End Sub
Click to expand...
Hope someone could help me out with the right way to do this.
Thanx.
Click to expand...

Hi Sooraj,
To use Command prompt, you'd better use Shell instead of Process
class[Process class wants exact path of cmd.exe(c:\windows
\system32\cmd.exe..... unlike Shell)].

So, it would be like this:
Shell("cmd /k madymo601 filepath",AppWinStyle.NormalFocus)

And make sure you include exact path of your application to launch. I
mean, for example if you application (madymo601) resides as c:
\madymo601.exe then you should use:

Shell("cmd /k c:\madymo601 filepath",AppWinStyle.NormalFocus)

Hope this helps,

Onur Güzel
Click to expand...

Correcting my last post, you should use:(just added missing .exe
extension which you may not need)
Shell("cmd /k c:\madymo601.exe filepath",AppWinStyle.NormalFocus)

for the assumption above.

Onur
 
Process takes a file to execute in the call you are using. You are passing
the entire command line, which is why it did not work.

If I were youI would do it as follows:

Dim p As New Process
p.StartInfo.FileName = "cmd"
p.StartInfo.Arguments = "/k madymo601 TheInputFile"
Process.Start
 
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