How to initialize "public const short[] test"?

[babylon]

I can't do
public const short[] test = new short[]{1000,2000,3000};

any suggestions?

thx

 

[Frank Oquendo]

any suggestions?

public readonly short[] test = new short[] {1000, 2000, 3000};

--
There are 10 kinds of people. Those who understand binary and those who
don't.

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[babylon]

oic ...
then it should be
public static readonly short[] test = new short[] {1000, 2000, 3000};
as a const member is static

thank you!

any suggestions?

public readonly short[] test = new short[] {1000, 2000, 3000};

--
There are 10 kinds of people. Those who understand binary and those who
don't.

http://code.acadx.com
(Pull the pin to reply)

 

[Don Dumitru [MSFT]]

If you have a really complicated init that you need to run for a const
member, you can write a static method which returns the result.

private static short[] InitTest() {
short[] res = null;
// do lots of complicated stuff here
return res;
}
public const short[] test = InitTest();

--Don

 

[Jon Skeet [C# MVP]]

If you have a really complicated init that you need to run for a const
member, you can write a static method which returns the result.

private static short[] InitTest() {
short[] res = null;
// do lots of complicated stuff here
return res;
}
public const short[] test = InitTest();

No you can't, because "const" can't apply to arrays. Even if it could,
it *really* couldn't apply to something like the above, as "const"s are
meant to be *compile-time* constants.