How to determinate a integer odd or even

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Hi,
How to determinate a integer odd or even in c#?

 

[Jon Skeet [C# MVP]]

How to determinate a integer odd or even in c#?

boolean even = ((x & 1)==0);

 

[Nicholas Paldino [.NET/C# MVP]]

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Simple:

// See if integer i is odd or even:
bool even = ((i % 2) == 0);

Hope this helps.

 

[Michael Klingensmith]

You can determine this by using the modulo operator %

int i = 1;
bool isEven = (i % 2 == 0);
isEven will be false

int i = 2;
bool isEven = (i % 2 == 0);
isEven will be true meaning it is even.

Michael Klingensmith
http://www.seeknsnatch.com

 

[John Timney \(MVP\)]

int nNumber = 5;

if(nNumber % 2 == 0)
{
// even
}
else
{
// odd
}

 

[Lebesgue]

boolean even = ((x & 1)==0);

He asked about C#, not Java, Jon ;-) (OK, I know you are writing much more
code in Java than in C# these days )

 

[Jon Skeet [C# MVP]]

He asked about C#, not Java, Jon ;-) (OK, I know you are writing much more
code in Java than in C# these days )

Doh

bool even = ((x&1)==0);

It's worth knowing the &1 instead of %2 trick, for the occasional
performance-intensive bit of code. It can make quite a difference...

 

[firemyst]

Here’s a blog article which benchmarks quite a few ways to test if a number is odd or even:
blogs ^ davelozinski ^ com/curiousconsultant/csharp-net-fastest-way-to-check-if-a-number-is-odd-or-even


There are actually numerous ways to do this. Surprisingly, the fastest way appears to be the modulus % operator, even out performing the bitwise ampersand &, as follows:

if (x % 2 == 0)
total += 1; //even number
else
total -= 1; //odd number

Definitely worth a read for those that are curious.

 

[firemyst]

The link is now:

cc davelozinski com/c-sharp/fastest-way-to-check-if-a-number-is-odd-or-even