how to access footertemplate row of a datagrid

  • Thread starter Thread starter shiv
  • Start date Start date
S

shiv

Hello all,

I am just wondering how to access FooterTemplate row
inside a datagrid programatically as i need to get hold
of TextBox control which is embedded inside the footer
column.

does anybody has any idea on the same?
thanks in advance
regards
shivanand
 
Hello all,

I am just wondering how to access FooterTemplate row
inside a datagrid programatically as i need to get hold
of TextBox control which is embedded inside the footer
column.

does anybody has any idea on the same?
thanks in advance
regards
shivanand
Click to expand...
private void dgPackage_ItemCommand(object source,
System.Web.UI.WebControls.DataGridCommandEventArgs e)
{
if(e.CommandName == "Insert")
{
DropDownList ddlLabel = (DropDownList)
e.Item.FindControl("Dropdownlist1");

Assuming that Dropdownlist1 is the name of the control.....
 
Thanks Hills,

But Here, I have a textBox Control within a FooterTemplate
column and that is not considered as an Item(its not
figured in list of items). Moreover i have to access this
on a click of a button not on any event associated with
DataGrid itself. Hope this gives you more insight into my
problem.

regards
 
Thanks Hills,

But Here, I have a textBox Control within a FooterTemplate
column and that is not considered as an Item(its not
figured in list of items). Moreover i have to access this
on a click of a button not on any event associated with
DataGrid itself. Hope this gives you more insight into my
problem.

regards
Click to expand...


Ok, all the following goes in the html.

<script>
function doArtistSearch(pField){
var returnValue="";

returnValue=window.showModalDialog('dlgArtistFrame.html',window,
"dialogHeight:350px; dialogWidth:380px;
resizable:no;scroll:no;status:no;center:yes");
if(returnValue != "" && returnValue !=null){

document.getElementById("txtSearchArtist").value=returnValue;
var data = returnValue.split("~");
document.getElementById(pField).value=data[1];
}
}
</script>

That is a function that accepts the name of the textbox. It opens a
search dialog which returns an artist code and name separated by ~.
PS I know I don't need a param but this was once going to be used with
more than one pair of columns. Since it isn't, I hard-coded
txtSearchArtist and forgot to the same with the name field....

I have a hidden column with the artistcode and this is the footer
template for the name.

<FooterTemplate>
<input name="btnArtist" type="image" src="images/iconSearch.gif"
OnClick="doArtistSearch('txtArtist');return(false)">
<input type="text" name="txtArtist">
</FooterTemplate>

Not these are not asp controls. The code I posted earlier demonstrates
how to read these non-asp controls back at the server.

Basically the rest of the grid is normal, the footer row I use as a
new row to allow adding a new record.

HTH
 
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