G Guest Jan 12, 2005 #1 I think it takes 160 seconds ideally. Do you agree? 20G = 20,000MB = (20,000*8)Mb = 160,000Mb 160,000Mb/100Mbps = 160s
I think it takes 160 seconds ideally. Do you agree? 20G = 20,000MB = (20,000*8)Mb = 160,000Mb 160,000Mb/100Mbps = 160s
P Pegasus \(MVP\) Jan 12, 2005 #2 Dave said: I think it takes 160 seconds ideally. Do you agree? 20G = 20,000MB = (20,000*8)Mb = 160,000Mb 160,000Mb/100Mbps = 160s Click to expand... Whip out your calculator. 160,000 / 100 = 1,600, not 160! In real life, you get transfer speeds of 5..10 MBytes/s. Your actual transfer time will be 35..65 minutes.
Dave said: I think it takes 160 seconds ideally. Do you agree? 20G = 20,000MB = (20,000*8)Mb = 160,000Mb 160,000Mb/100Mbps = 160s Click to expand... Whip out your calculator. 160,000 / 100 = 1,600, not 160! In real life, you get transfer speeds of 5..10 MBytes/s. Your actual transfer time will be 35..65 minutes.
B Bob I Jan 13, 2005 #3 As Pegasus says 1,600 seconds but divide by "efficiency of system" at 50 -70 % so 2300 seconds to 3200 seconds for reasonable system
As Pegasus says 1,600 seconds but divide by "efficiency of system" at 50 -70 % so 2300 seconds to 3200 seconds for reasonable system
