How identify active control name

  • Thread starter Thread starter Woody Splawn
  • Start date Start date
W

Woody Splawn

I know that I can do the following to identify the parent name of an active
control

Dim sParentName As String = ActiveControl.Parent.Name

But how do I identify the name of the active control?

Str = activeControl.Name

does not seem to work.
 
* "Woody Splawn said:
I know that I can do the following to identify the parent name of an active
control

Dim sParentName As String = ActiveControl.Parent.Name

But how do I identify the name of the active control?

Str = activeControl.Name

does not seem to work.
Click to expand...

Why doesn't it work? Error message?
 
I'm sorry, I gave you incorrect information. It does work when I use it,
for example, on a txtbox on a field on a winform but I am trying to make it
work for a field on a datagrid. That is, I am on a datagrid and I would
like to identify the field on the datagrid that I am on. I assume that is
considered by VS as the ActiveControl. My intent is to leave it and then
return to it. When I use code like the following under those circumstances
I get a result of nothing.

Str = activeControl.Name

Dim sParentName As String = ActiveControl.Parent.Name gives me the name of
the datagrid but I would like the field on the datagrid that I am currently
on.

Thank you in advance for your help.
 
Hi Woody,

Based on my understanding ,you want to know what field is the cell you are
selecting in.
I think you may try to get it from the datasouce. e.g. it is a dataset

Private Sub DataGrid1_CurrentCellChanged(ByVal sender As Object, ByVal
e As System.EventArgs) Handles DataGrid1.CurrentCellChanged

MsgBox(DataSet11.Tables(0).Columns(DataGrid1.CurrentCell.ColumnNumber).Colum
nName)
End Sub

Did I misunderstand you meaning?
If you have related question, please feel free to let me know.

Regards,
Peter Huang
Microsoft Online Partner Support
Get Secure! www.microsoft.com/security
This posting is provided "as is" with no warranties and confers no rights.

--------------------
 
Hi Woody,

Did my suggestion works for you?
If you have any related question, please feel free to let me know.

Regards,
Peter Huang
Microsoft Online Partner Support
Get Secure! www.microsoft.com/security
This posting is provided "as is" with no warranties and confers no rights.
--------------------
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References: <[email protected]>
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Organization: Microsoft
Date: Tue, 14 Oct 2003 07:57:25 GMT
Subject: Re: How identify active control name
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Hi Woody,

Based on my understanding ,you want to know what field is the cell you are
selecting in.
I think you may try to get it from the datasouce. e.g. it is a dataset

Private Sub DataGrid1_CurrentCellChanged(ByVal sender As Object, ByVal
e As System.EventArgs) Handles DataGrid1.CurrentCellChanged

MsgBox(DataSet11.Tables(0).Columns(DataGrid1.CurrentCell.ColumnNumber).Colu m
nName)
End Sub

Did I misunderstand you meaning?
If you have related question, please feel free to let me know.

Regards,
Peter Huang
Microsoft Online Partner Support
Get Secure! www.microsoft.com/security
This posting is provided "as is" with no warranties and confers no rights.

--------------------
From: "Woody Splawn" <[email protected]>
References: <[email protected]>
Click to expand...
Subject: Re: How identify active control name
Date: Mon, 13 Oct 2003 15:13:45 -0700
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I'm sorry, I gave you incorrect information. It does work when I use it,
for example, on a txtbox on a field on a winform but I am trying to make it
work for a field on a datagrid. That is, I am on a datagrid and I would
like to identify the field on the datagrid that I am on. I assume that is
considered by VS as the ActiveControl. My intent is to leave it and then
return to it. When I use code like the following under those circumstances
I get a result of nothing.

Str = activeControl.Name

Dim sParentName As String = ActiveControl.Parent.Name gives me the name of
the datagrid but I would like the field on the datagrid that I am currently
on.

Thank you in advance for your help.
Click to expand...
Click to expand...
 
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