How do I get from the sine of an angle to the actual angle

  • Thread starter Thread starter JungleJim74
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JungleJim74

I have been struggling with this for several days but have been unable to do
it. I have downloaded and installed the VB Express Edition 2008 so that I
could use the "truncate" method. For example, in a right triangle with
opposite side of 6.0, adjacent side of 8.0, and a hypotenuse of 10.0 the sine
of theta is 6.0 / 10.0 or 0.6. This gives me the sine of the angle but just
how do I get the angle whose sine is 0.6? I can look it up in the Trig tables
but I need to be able to do it with DOTNET program code. I sure need some
help on this and thanks in advance for any help.
 
JungleJim74 said:
I have been struggling with this for several days but have been unable to do
it. I have downloaded and installed the VB Express Edition 2008 so that I
could use the "truncate" method. For example, in a right triangle with
opposite side of 6.0, adjacent side of 8.0, and a hypotenuse of 10.0 the sine
of theta is 6.0 / 10.0 or 0.6. This gives me the sine of the angle but just
how do I get the angle whose sine is 0.6? I can look it up in the Trig tables
but I need to be able to do it with DOTNET program code. I sure need some
help on this and thanks in advance for any help.
Click to expand...

Use Math.Asin(0.6)

That returns radians, so you may need to convert depending on your
application.

You should look into the documentation here:
http://msdn.microsoft.com/en-us/library/system.math_methods.aspx

Mike
 
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