Help with wildcard Replace syntax, please?

  • Thread starter Thread starter Ed from AZ
  • Start date Start date
E

Ed from AZ

I tried a wildcard Find/Replace:
-- Find: 5 spaces, any combination of 2 numbers, a period
( {5,})[0-9]{2,}.
-- Replace: 9 spaces, then "a."
( {9})a.

Find worked. Replace gave me: " {9}a."

I gave up trying to code it and just typed 9 spaces! 8>/
Is there something special I needed to do in the Replace box?

Ed
 
You must enter into the Replace box exactly what it is that you want to be
used as the replacement

Though, you could have used

([ ]{4}) [0-9]{2}

in the Find what control and then

\1\1 a

in the Replace with control

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP, originally posted via msnews.microsoft.com
 
Hi Ed from AZ,

You can't use the character count expression in the Replace field - you need to explicitly input the # characters or, as Doug has
done, employ a suitable expression from the Find field.
 
Thanks, Doug, macropod, and Graham. I've tried to master the wildcard
Find - but forgot to spend time on Replace! (Other than the ^13 - ^p
gotcha that was explicitly called out.)

Cheers!
Ed
 
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