Here's one really, really long formula you can use:
=MID(A1,FIND("(",A1)+1,FIND(")",A1)-FIND("(",A1)-1)+MID(A1,FIND("(",A1,FIND("(",A1)+1)+1,FIND(")",A1,FIND(")",A1)+1)-FIND("(",A1,FIND("(",A1)+1)-1)+MID(A1,FIND("(",A1,FIND("(",A1,FIND("(",A1)+1)+1)+1,FIND(")",A1,FIND(")",A1,FIND(")",A1)+1)+1)-FIND("(",A1,FIND("(",A1,FIND("(",A1)+1)+1)-1)
However, this is only good for three sets of numbers. If you go to four it gets much worse.
If you want to keep it more manageable you could break down the above into multiple components:
B1
osition of first ( =FIND("(",A1)
C1
osition of first ) =FIND(")",A1)
D1
osition of second ( =FIND("(",A1,B1+1)
E1
osition of second ) =FIND(")",A1,C1+1)
F1
osition of second ( =FIND("(",A1,D1+1)
G1
osition of second ) =FIND(")",A1,E1+1)
H1:First Number =MID(A1,B1+1,C1-B1-1)
I1:Second Number =MID(A1,D1+1,E1-D1-1)
J1:Third Number =MID(A1,F1+1,G1-F1-1)
Total =H1+I1+J1 (note: you can't use SUM for this step)
Good Luck,
Mark Graesser
(e-mail address removed)
----- bjack56 wrote: -----
I have the following information in a CELL, let's call it A1. These are
just project dates with working hours in ( ).
12/1(5.5),12/5(10.5),12/10(4)
In cell A2 I would like a formula that totals only the numbers inside
the ( ) in a single cell. The above example would = 20.0