Handling Exception

[Franz]

try
{
}
catch (ExceptionA A)
{
XXXXXXXXXXXXX
}
catch (ExceptionB B)
{
XXXXXXXXXXXXX
}
catch (Exception)
{
YYYYYYYYYYYYY
}

Actually the codes of hanlding both Exception A and B are same. I want to
put it in a single catch block. Although I know that I can group the code
into a function and call it in these two catch blocks, I don't want to have
duplicated code. Also I don't want to give a inheritance relationship for
both ExceptionA and ExceptionB. I

Is there anything like the following? I want to do the following because if
a large number of exception use the same hanlding code, then I can group
them into a small number of brackets.

try
{
}
catch (ExceptionA A)
catch (ExceptionB B)
{
XXXXXXXXXXXXX
}
catch (Exception)
{
YYYYYYYYYYYYY
}

Thanks.

 

[Andrew Gnenny]

Here is my vision:

try
{
}
catch(Exception E)
{
if ((E is ExceptionA) || (E is ExceptionB))
{
XXXXXXXXXXXXX
}
else
{
YYYYYYYYYYYYY
}
}

 

[Eric Gunnerson [MS]]

Unless you have an inheritance relation, there is no way to do this.

--
Eric Gunnerson

Visit the C# product team at http://www.csharp.net
Eric's blog is at http://blogs.gotdotnet.com/ericgu/

This posting is provided "AS IS" with no warranties, and confers no rights.

 

[Franz]

Yes, you are right.
Finally, I accept the following solution.

catch (Exception e)
{
switch (e.GetType().ToString())
{
case "ExceptionA":
case "ExceptionB":
Console.WriteLine("This is Exception A and B");
break;
}
}