Thank you Miha, it now works. You are always quick to respond and are very helpful to somebody who is new to .NET.
Brad
"Miha Markic" <miha at rthand com> wrote in message Hi Brad,
You sure that your code is correct - I mean you look at the right guid?
NewGuid generates random GUID and not empty one.
You should do:
Dim g as Guid = Guid.NewGuid()
Console.WriteLine(g)
--
Miha Markic - RightHand .NET consulting & software development
miha at rthand com
Jennifer,
Thanks for the help, but every time I run this method, I get the following for a GUID: 00000000-0000-0000-0000-000000000000. I was under the understanding that this method was in a way like RANDOMIZE. Am I missing something?
Thanks again for the information.
Brad
Check out the Guid.NewGuid Method:
http://msdn.microsoft.com/library/d...ref/html/frlrfSystemGuidClassNewGuidTopic.asp
-- thanks~
Jennifer Perret [MS]
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I usually use numerics with a random number generator for my unique ID fields in my tables, however I have an instance where I would like to use GUIDs (since this key will never be used or seen by the end user). Here is the start of my code:
Dim myGuid1 As New Guid()
JrEventID = myGuid1.ToString
txtEventID.Text = JrEventID
How do I generate a new GUID? Is is a simple process?
Thanks for the information.
Brad