M
MarkCapo
Using Access XP you call the currentproject method and
pick up its name property to return the filename of the
current application file. I need to to a similar
function in 97 which only picks up the filename directly
rather than using a procedure that loops through the path
and filename to pick out filename from the
application.name result.
Can anybody help with this!
Thanks
mark
pick up its name property to return the filename of the
current application file. I need to to a similar
function in 97 which only picks up the filename directly
rather than using a procedure that loops through the path
and filename to pick out filename from the
application.name result.
Can anybody help with this!
Thanks
mark