Function question???

  • Thread starter Thread starter karim
  • Start date Start date
K

karim

I have this function to zoom an image in my form, but I can't get it to work.
can anyone tell me how to get it to work or what's wrong with it. also i'm
getting this erorr msg: (local variable cannot have the same name as the
function containing it)
here is the code:

Public Function ZoomImage(ByVal img As System.Drawing.Image, ByVal ZoomValue
As Int32) As System.Drawing.Image
Dim width As Int32 = Convert.ToInt32(img.Width * ZoomValue) / 100
Dim height As Int32 = Convert.ToInt32(img.Height * ZoomValue) / 100
'Create a new image based on the zoom parameters we require
Dim zoomImage As New System.Drawing.Bitmap(img, width, height)

'Create a new graphics object based on the new image
Dim converted As System.Drawing.Graphics =
System.Drawing.Graphics.FromImage(zoomImage)

'Clean up the image
converted.InterpolationMode = InterpolationMode.HighQualityBicubic

'Return the zoomed image
Return zoomImage
End Function
 
karim said:
also i'm getting this erorr msg: (local variable cannot have
the same name as the function containing it)
Click to expand...
Public Function ZoomImage(...
Dim zoomImage As ...
Click to expand...

Start by changing the name of the variable zoomImage. VB is not
case-sensitive.

Andrew
 
Start by changing the name of the variable zoomImage. VB is not
case-sensitive.

Andrew
Click to expand...

I think changing function name "ZoomImage" to something like
"ZoomImageFunc" or anything should help based on the error which OP
describes.

Because function returns zoomImage variable which is declared as:
Dim zoomImage As New System.Drawing.Bitmap(img, width, height)

...inside function-end function block.

Thanks,

Onur Güzel
 
kimiraikkonen said:
I think changing function name "ZoomImage" to something like
"ZoomImageFunc" or anything should help based on the error which OP
describes.

Because function returns zoomImage variable which is declared as:
Dim zoomImage As New System.Drawing.Bitmap(img, width, height)
Click to expand...

Hmmm... I would have thought that the external appearance of the function
(its name) should take precedence over the names of the variables used
inside that function, hence my suggestion to change the name of the variable
rather than the function.

Also, I thought that using the type of a variable/function in its name had
gone out of fashion?

ICBW...

Andrew
 
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