Confused,simple math formula

  • Thread starter Thread starter Richard
  • Start date Start date
R

Richard

If I have a 379 liter tank (K3) filled with water and I need 1.0 grams
per liter (D3) to have the correct amount in the tank. If I'm over
(B3) lets say 1.9 grams per liter. I need to decrease (G3) by .9 grams
per liter. Since it's already mixed,how would I get J3 to show the
amount of Gals removed to bring it back to (D3) 1 gram per liter. I
thought k3*g3/d3/3.78 would work but if it's 2.0 grams over(B3) then
is says to add 100 gals. 100 gals is the entire tank size. If I did
that I'd need to add 1 gram per liter. Confused!? Thanks so much for
your help!!!
 
As I read this,  realized that your primarily problem was with the use
of language rather than arithmetic. It starts out with a convoluted
incomplete sentence. Revise and reask your question.

Bill
Click to expand...

May I ask where my incomplete sentence is so I can trouble shoot from
there?
 
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