message |
| | > In article
| > (e-mail address removed) says...
| > > In article <
[email protected]>,
| > > (e-mail address removed) says...
| > > > Do you understand how a linear regulator works?.
| > >
| > > Yea, I if I take the 7812, 7805, LM317, etc... regulator device,
and
| > > look in my Linear data book, it's the same as it's been since
the
| 80's.
| > > The device does not disapate heat or waste anything to provide
the
| > > specified power from the supply voltage.
| > >
| > > I don't see it as disapating anything to provide the drop to the
| > > requested level, I see it disapating heat to provide the X volts
at y
| > > MA, through the circuit. The drop doesn't generate the heat, the
load
| on
| > > the regulator does.
| It is the product of the current, and the voltage drop.
|
| > One thing to keep in mind, the OP said the cap was blown and in my
| > experience, if it was part of the switching power circuit, it
would
| > almost certainly mean problems for his system.
| >
| > Since he's not having any problems with it, then it must be OPEN
and not
| > shorted and certainly not doing it's job. This leads me to believe
that
| > it's just for filtering ripple on the board at some critical point
that
| > requires flat voltage levels.
| >
| > One last thing, if I setup a 7805 or LM317 regulator, and supply
it with
| > 12VDC and set the output to 5V, the heat generated under a 1A load
is no
| > different than when I supply it with a 24VDC input.
| You really don't understand it do you. On a 1A load from a 12v
input, a
| 7805, will have to dissipate 7W. From a 24v supply, it'll have to
| dissipate 19W. The heat most definately _is_ different.
|
|
|
Roger is correct, a switching PS circuit is far more "efficient" than
a traditional linear regulator circuit. Roger's explanation is
technically accurate in all respects. Since the cap in issue is near
the agp slot, I suspect it is not being used in a switching PS
circuit.
A review of a LM341/7805 datasheet
http://www.national.com/ds/LM/LM341.pdf reveals the following heat
dissipation formula:
PD = (VIN-VOUT) IL + VIN*IG
PD=Power Dissipation
VIN=input voltage
VOUT=output voltage
IL= load current driven into the "load"
VIN*IG=input voltage * Ig (regulator current usage)
It should be clear that the difference between Vin and Vout directly
and linearly impacts heat dissipation in the device.