The power supply is split in two halves. The main rails are one half of
the
design (and support "soft off", where the computer can turn off the power
for itself on the main rails). The standby source is the other half. The
standby source runs all the time, until the AC is interrupted. The standby
source doesn't require the fan on the power supply to be running, as it is
intended to be a relatively low power output circuit with not a lot
of waste heat.
230VAC ---- PSU ---- +3.3,+5,+12,-12 (rails used when computer
running)
Box ---- +5VSB ---+ (+5VSB is the standby voltage)
|
| -->
+------Diode---+
|
+--------- CMOS RAM and
RTC
--> |
CR2032 battery ------Diode---+
The diode scheme selects the path with the highest voltage. If you've done
something to interrupt +5VSB (switch off at the back of the computer, or
flip the switch on the power strip), then the CMOS RAM and RTC will run
from battery. And that shortens the life of the battery.
The CR2032 still has a finite shelf life, even if no current is being
drawn. But if you put the computer in storage, with the CR2032 battery
left in place, then expect the battery to last about 3 years. That is how
long mine lasted, on two different computers in storage.
(The above diagram has been simplified a bit, by removing details about
a regulator just after +5VSB. The CMOS doesn't actually run from 5V,
but gets a voltage a bit higher than the 3V from the battery. The
regulator just after +5VSB might be delivering 3.3V, and that causes it
to be the preferential current flow path through the diodes. One of the
diodes ends up reverse biased, which is how the diodes manage the source
of current in this scheme.)
There is a motherboard schematic here. PDF page 85, shows the regulator
that takes 5VSB and makes 3.3V from it. The upper left corner of PDF page
82,
shows the diodes selecting the battery or +5VSB derived source of power
for the CMOS. You don't need to download this, unless you're really
really curious
http://www.intel.com/design/chipsets/schematics/252812.htm
Paul