L
Leo Karl
Come to find out that this query:
SELECT first.cname, second.cname, first.rating
FROM Customers AS first, Customers AS second
WHERE first.rating = second.rating;
Will work under ANSI-89, but produces a syntax error when run under ANSI-92.
Can anyone tell me how to code it for running under ANSI-92?
Thanks, Leo
SELECT first.cname, second.cname, first.rating
FROM Customers AS first, Customers AS second
WHERE first.rating = second.rating;
Will work under ANSI-89, but produces a syntax error when run under ANSI-92.
Can anyone tell me how to code it for running under ANSI-92?
Thanks, Leo