3rd attempt: Exception in Timer.Tick/JIT debugging

  • Thread starter Thread starter Armin Zingler
  • Start date Start date
A

Armin Zingler

Hi,

as nobdoy answered again, again the short version:

1. Add a Timer (System.Windows.Forms.Timer) to a new WindowsApplication.
2. Set the timer's Enabled property = True.
3. In the timer's tick event, write:
Throw New Exception
4. Start

How can I have the IDE handle the exception? That's what I expect but I
don't have a chance.


Armin
 
Tim Mackey said:
hi Armin,
i can't reproduce your situation. my app shows the normal unhandled
exception dialog box.
Click to expand...


This is not the IDE. This is the "JIT debugging" dialog, as you can see
here:
http://people.freenet.de/armin.zingler/jitdebugging.PNG
(buttons mean details, continue, quit.)
I want the *IDE* to handle the exception like everywhere else. It does *not*
handle the exception if it occurs in a timer's tick event.

If I throw the exception in a button's click event instead, the IDE dialog
occurs:
http://people.freenet.de/armin.zingler/ide.png
I can press the first button (means "break") and the cursor is on the line
throwing the exception. That's how I expect it to be. This is not possible
with the 1st dialog.
are you sure you created the form on the UI thread?
Click to expand...

My example shows how I did it. That's all. There are no other threads.

I read the rest of your post but that's currently not the point.


If my example runs without a debugger attached, I also get the 1st dialog,
if the exception is in the timer tick event wherease I get the usual dialog
if it's anywhere else (like in a button's click event):
http://people.freenet.de/armin.zingler/exceptionnodebugger.png

I don't understand this dictinction made.

Armin
 
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